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senlin2684 发表于 2008-12-22 17:58

怎样在findall中加入distinct参数

$sql = "select count(distinct filmid) as cn from torrent_movies where ".$conditions;

有类似于这样的运用,请问如何运用 function & findAll($conditions = null, $sort = null, $limit = null, $fields = '*', $queryLinks = true)来实现,主要是如何传参。

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